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Cambridge IGCSE Mathematics — 0580 Extended

Topic 4.2: Geometry — Constructions

Measuring and drawing lines and angles

Use a ruler for every straight edge — including the sides of a triangle after the compass arcs have located a vertex. Use a protractor to measure or draw an angle. A pair of compasses draws an arc of a fixed radius (every point on the arc is the same distance from the centre).

You are not required to construct a perpendicular bisector or an angle bisector. Those constructions are outside this syllabus.

Method

  1. Mark the two endpoints, then join them with a single rulered line. Do not freehand a “straight” side.
  2. To draw an angle, place the protractor’s centre on the vertex and the zero-line along the given ray; mark the size and join with a ruler.
  3. Read lengths to the nearest millimetre and angles to the nearest degree unless the question says otherwise.

Constructing a triangle given three sides (SSS)

Given three side lengths that satisfy the triangle inequality, there is a unique triangle (up to reflection). Locate the third vertex with two compass arcs; then join with a ruler. The construction arcs must stay on the diagram.

Method

  1. Draw one side as a base with a ruler (any of the three sides; here \(BC\)).
  2. Open the compasses to the second length. With centre at one end of the base, draw an arc.
  3. Open the compasses to the third length. With centre at the other end, draw a second arc so the two arcs cross.
  4. The intersection is the third vertex. Join it to both ends of the base with a ruler.

Construct triangle \(ABC\) with \(AB = 4\,\text{cm}\), \(BC = 5.3\,\text{cm}\) and \(AC = 4.7\,\text{cm}\).

SSS construction of triangle ABC: base BC with a compass arc from B of radius AB and a compass arc from C of radius AC, intersecting at A
Draw \(BC\), then an arc centre \(B\) radius \(AB\) and an arc centre \(C\) radius \(AC\). \(A\) is an intersection.

Paper 2 (non-calculator)

Visible construction arcs carry a method mark. An accurate-looking triangle with the arcs rubbed out scores fewer marks than a slightly imperfect triangle with the arcs still shown.

Constructing a rhombus from two triangles

A rhombus has four equal sides. It is two congruent triangles sharing a diagonal. Construct each triangle by SSS, on opposite sides of that diagonal.

Method

  1. Draw diagonal \(AC\) with a ruler (use the given length, or choose one if only the side is given).
  2. Construct \(\triangle ABC\) by SSS: arcs from \(A\) and from \(C\), each with radius equal to the side of the rhombus.
  3. Repeat on the other side of \(AC\) to locate \(D\). Join \(AB\), \(BC\), \(CD\) and \(DA\) with a ruler.
  4. Leave every construction arc visible.

If the rhombus is made of two equilateral triangles, every side and the shared diagonal are equal, and the angles are \(60^\circ\) and \(120^\circ\).

Nets of cubes, cuboids, prisms and pyramids

A net is a 2-D arrangement of faces that folds to make a solid, with no two faces occupying the same place. Draw every edge with a ruler. You must be able to sketch nets of a cube, cuboid, prism and pyramid.

A cube net uses six congruent squares. A cuboid net uses six rectangles (opposite faces equal). A prism net is two end-faces plus a strip of rectangles for the sides. A square-based pyramid net is a square with a triangle on each side.

Sketch a net of a cube.

Cross-shaped net of a cube made of six congruent squares, with the top and front faces labelled
Six congruent squares. Fold so that no two faces occupy the same place.

Sketch a net of a square-based pyramid.

Net of a square-based pyramid: a square base with an isosceles triangular face attached to each side
Square base and four isosceles triangular faces, one on each side of the square.

You can read lengths from a net and use them later for surface area or volume. Adding the areas of the faces on the net gives the surface area. Volume formulae belong in Chapter 5 — do not invent them here.

Try this

To construct \(\triangle PQR\) with \(PQ = 6\,\text{cm}\), \(QR = 8\,\text{cm}\) and \(PR = 7\,\text{cm}\), which side can you draw first, and which two arcs locate the third vertex? A cube net is made of squares of side \(3\,\text{cm}\). What is the surface area?

Show answer
Answer
  1. Any side as base; here \(PQ\). Then arc centre \(P\) radius \(PR\) and arc centre \(Q\) radius \(QR\)

    \[ R \text{ is an intersection of the two arcs} \]
  2. Six faces, each \(3 \times 3\)

    \[ 6 \times 9 = 54 \]
  3. Surface area from the net

    \[ 54\,\text{cm}^2 \]

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